一道因式分解题

a^4x^2-a^4y^2=a^4(x^2-y^2)=a^4(x+y)(x-y)

原式=a^4*(x^2-y^2)=a^4*(x+y)*(x-y)

a^4x^2-a^4x^2=0,题目抄错?如果是a^4x^2-a^2x^4,则a^4x^2-a^2x^4=a^2*x^2*(a^2-x^2)=a^2x^2(a+x)(a-x)。

a^4x^2-a^4y^2=a^4*(x^2-y^2)=a^4*(x+y)*(x-y).