矩阵键盘在数码管上显示1-16的平方,只显示个位

while(1) { aa1 = fanhui();display(bai, shi, ge);//用显示，当延时，消抖. aa2 = fanhui();//再读. if (aa1 == aa2) aa = aa1;//两者相等，确认到aa－－－－－－－－－如果不相等呢？aa = ？ i = aa * aa;bai = i / 100;shi = (i % 100) / 10;ge = i % 10;display(bai, shi, ge);}另外，按键检测程序太长了！4*4的，程序可以在10行之内（不包括大括号占的行数）。到我的空间找找看。 **************************************************好了。你的延时函数里面的：for，都写成什么了？//-----------------------------------------------------void delay(uint z){ uint x, y;for (x = z;x >0;x--) for (y = 110;y >0;y--);}//-----------------------------------------------------void display(uchar bai, uchar shi, uchar ge){ wela = 1;P0 = 0xff;wela = 0;//消隐. dula = 1;P0 = table[bai];dula = 0;wela = 1;P0 = 0xfd;wela = 0;delay(10);wela = 1;P0 = 0xff;wela = 0;dula = 1;P0 = table[shi];dula = 0;wela = 1;P0 = 0xfb;wela = 0;delay(10);wela = 1;P0 = 0xff;wela = 0;dula = 1;P0 = table[ge];dula = 0;wela = 1;P0 = 0xf7;wela = 0;delay(10);} //-----------------------------------------------------void main(){ while(1) { i = 128;bai = i / 100;shi = (i % 100) / 10;ge = i % 10;display(bai, shi, ge);}} //----------------------------------------------------- 收起